Question

A barge, 40 metres long and 8 metres broad, whose sides are vertical, floats partially loaded in water. If 125000N of cargo is added, how many metres will it sink?​

Answer 1

Answer:

it is four met

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Answer 2

Answer:

Area Of Barge  A  = Length x Width

          //             A  = 40m x 8m  

         //              A  = 320m²

Additional Weight 'w' Of Cargo = 125000N

Increase Upthrust Force'F' Must Be Equal To The Additional Load . Hence ,

                          F  = ρVg

                          F  = w

                     ρVg  = w

1000kg/m³ x V v 10m/s² =125000N

                         V  = 12.5m³  

Depth h To Which Barage Sinks = h=  V/A

                             h  = 12.5m³/320m²

                             h  = 0.04m

                             h  = 4cm    

Explanation:

Hope Now You Get Answer           >.<        O.o     @o@