A barometer kept in an elevator accelerating upward reads 76 cm. The air pressure in the elevator is
(a) 76 cm
(b) <76 cm
(c) >76 cm
(d) zero.
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Answer ⇒ Option (c).
Explanation ⇒ When the elevator is accelerating upward, then Pressure of atmosphere will be equal to,
P₀ = hρ(g + a)
where h = 76 cm.
Now, At Ordinary conditions pressure of the atmosphere is given by,
P = hρg, h = 76 cm.
Now, we can see P₀ > P, because of g + a.
Thus, P < 76 cm
Hence, Option (c). is correct.
Hope it helps.
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