Question

A barometer reads 76 cm at the sea level. If g = 10 ms$^{2}$, and density of mercury is 13.6 gcm$^{–3}$. What is the pressure of air in SI system ?​

Answer 1

Given:

Height of mercury column (h) = 76 cm = 0.76 m

Density of mercury (d) = 13.6 gm$^{–3}$

= 13600 kgm$^{–3}$

Acceleration due to gravity (g) = 10 ms$^{2}$

To find:

Pressure of air in SI system.

Solution:

Pressure of air = Pressure of mercury (P)

And Pressure of mercury = h × d × g

$= 0.76 \: (m) \times 13600 \: (kgm {}^{ - 3} ) \times 10(ms {}^{ - 2}$

= 103360 Pa.

Thus, pressure of air in SI system = 103360 Pa.

Answer 2

Answer:

here is your answer hope it helps you