A barrel accelerates uniformly, from 10.0 m/s, 80.0 m down a hill reaching a speed of 15m/s.
How long it will take to do this?
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Given:-
- Initial velocity ,u = 10m/s
- Final velocity ,v = 15m/s
- Distance travelled ,s = 80m
To Find:-
- Time taken by the barrel ,t
Solution:-
Firstly we calculate the acceleration of the barrel.
So by using 3rd equation of motion
• v² = u² +2as
Substitute the value we get
→ 15² = 10² + 2×a ×80
→ 225 = 100 + 160×a
→ 225-100 = 160×a
→ a = 125/160
→ a = 0.78m/s²
Now using first equation of motion
• v = u+at
Substitute the value we get
→ 15 = 10 +0.78×t
→ 15-10 = 0.78×t
→ 5 = 0.78×t
→ t = 5/0.78
→ t = 6.41 s
∴ The time taken by the barrel is 6.41 Second.
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