Question

A base ball of 200 g is thrown to a batsman with a velocity of 20 m/s. The batsman hits harder and the ball moves with a velocity of 50 m/s in the opposite direction. Find the force exerted on the ball, if the force acts for 0.01 s?

Answer 1

$\sf\fbox{\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:Answer\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:}$

$\bold\pink{Given:}$

$\sf{Mass, (m) = 200 g}$

$\sf{Initial \: Velocity,(u) = - 20 m/s}$

$\sf{Final \: Velocity, (v) = 50 m/s}$

$\sf{Time ,(t) = 0.01 s}$

$\bold \pink{To\:Find: }$

$\sf{Force \: exerted (F) = ?}$

$\bold \pink{Solution: }$

$\bold{Formula\:used,}$

$\small\underline{\boxed{\sf\;\;Force = Mass \times Acceleration}}$

$\sf {Putting\:values\:in\:the\:formula:}$

$\sf \implies\sf Force = 200\:g \times \bigg\lgroup\dfrac{(Final\ -Initial)\ Velocity}{Time}\bigg\rgroup\\\\\\\implies\sf Force = \dfrac{200}{1000} \times \bigg\lgroup\dfrac{50 - ( - 20)}{0.01}\bigg\rgroup\\\\\\\implies\sf Force = \dfrac{2}{10} \times \dfrac{(50 + 20)}{ \frac{1}{100} }\\\\\\\implies\sf Force = \dfrac{2}{10} \times70 \times 100\\\\\\\implies\sf Force = 2 \times 7 \times 100\\\\\\\implies\sf Force = 1400 \:N$

$\sf{Hence,}$ $\sf{Force \: exerted \: on \: the \: base \: ball \: is \: 1400 \: N}$

Answer 2

Answer:

Mass=200g

Initial velocity (u)=20m/s

Final velocity(v)=50m/S

Time=0.01s

Now,

Acceleration = v-u/t

=50-20/0.01

=30/0.01

=3000

Force = m × a

= 200 ×3000

=600000N