A base load power station of capacity 35 MW has annual output of 150 * 10^6 kWh. The plant capacity factor of the power plant is ____%.
Answers
Answered by
0
Answer : - 0.49
Capacity Factor = Actual output / Potential output
Actual annual output = 150 x 10^6 kWh = 150 x 10^6 x 3600 kJ
Potential output = 35 MW = 35 x 10^3 kW = 35 x 10^3 x kJ/sec
Potential output = 35 x 10^3 x (3600 x 24 x 365 sec) / 1 Year
Potential output = 35 x 10^3 x 3600 x 24 kJ for 1 Year
Capacity Factor = Actual output / Potential output
Capacity Factor = (150 x 10^6 x 3600)/ (35 x 10^3 x 3600 x 24)
Capacity Factor = 0.49
Similar questions
Science,
7 months ago
Accountancy,
7 months ago
Computer Science,
7 months ago
Physics,
1 year ago
Math,
1 year ago