Question

A baseball is popped straight up into the air and has a hang-time of 6 s. Determine the maximum height to which the ball rises.

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Answer 1

The correct option is C

45 m

Time taken to reach the maximum height =

6

2

= 3 s

Final velocity, v = 0

Using first equation of motion, v = u + at

0 = u - 10

×

3

u = 30 m/s

Now,

s = ut +

1

2

a

t

2

s= 30

×

3 –

1

2

×

10

×

3

×

3

Hence, s = 90 – 45 = 45 m

Answer 2

Answer:

9

Explanation:

m= 6

v= 4

mgh= 10

6×4×10 = 420