Question

a baseball is popped straightu up into the air and has hang time 6.5 second determine the height to which the ball Rises before it reaches to peak hint the time to rise to the peak is one half to the total hang time​

Answer 1

Step-by-step explanation:

48.0m

As the hang time is the total time to reach peak and come back, so the time for reaching to peak is half of the hang time i.e. t=6.25/2=3.125s

When the ball reaches to peak point, the final velocity will be zero. i.e. v=0m/s

Here, the acceleration of ball is a=−g=−9.8m/s

2

(minus for motion against gravity)

let u be the initial velocity of the baseball.

Using v=u+at,

0=u+(−9.8)(3.125)

⟹ u=30.625m/s

If h be the height reached by ball.

Using v

2

−u

2

=2ah

0

2

−(30.625)

2

=2(−9.8)h

⟹ h=47.85m∼48m