Question

A baseball is thrown with an initial velocity of 100 m/s at an angle of 300 above the horizontal. How far from the throwing point will the baseball attain its original level?

Answer 1

Answer:

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Answer 2

Answer:

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Explanation:

Given,

Initial velocity =100m/s

Angle =300

So,

The initial velocity makes an angle 30° with horizontal. So,its vertical component will be 100sin30

0

=50m/s.

The time taken by the ball to acheive max height will be at a point when its vertical velocity will be zero. So Vsinx=at

T=

a

vsinx

=5seconds.

So after 5 seconds it will reach its max height.

Following the symmetry,it will land after 10seconds.

So the total horizontal distance covered will be vcosx×10≈866m

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