Question

A baseball of mass 150g travelling at 20 m/s is
caught by a fielder and brought to rest in 0.04s.
The force applied to the ball and the distance
over which this force acts are respectively.
1) 75N, 0.8 m
2) 37.5N, 0.4m
3) 75N, 0.4m
4) 37.5N, 0.8m​

Answer 1

v = u + at ( first equation of motion)

0 = 20+a(0.04)

a = -20/0.04

a = -500m/s^2

s = ut + 1/2 at^2

s = 1/2 × 500 × 0.04 × 0.04 = 0.4 m

F = m×a

F = 150/1000 × 500

F = 75 N

Hope it helps you....

Answer 2

Answer:

V=u+at

.....

a=75

f=ma

....

f=75

s=ut+1/2at^2

....

s=0.4

Explanation:

always remember kinematics equationd