Question

A baseball player got 102 hits in the last 300 times at bat. Explain how you would find the percent of times the baseball player got a hit out of the number of times at bat.

Answer 1

first of all the question is not specific it should be atleast how many times he would have got out
so I m assuming my condition
as what I said above
now total times the batsman didn't hit
=300-102
=198
In a baseball match the most hits for which you can bat without running is 3
as 3rd strike is out
198/3
=66
Now percent =66/300*100
=22
Hope it helps pls post the image of question next time if possible

Answer 2

Answer:

Divide the number of hits, 102, by the times at bat, 300. Then move the decimal 2 places to the right and add the percent sign to get 34%.

Step-by-step explanation: