Question

A baseball player hits a 0.15 kg baseball that is initially at rest, changing its momentum by 11 kg*m/s. What is the final speed of the baseball?

Answer 1

Answer:

GIVEN :

mass of the baseball = 0.15 kg

initial velocity (u) = 0 m/ s

Change in momentum (Δp) = 11 kgm/s

TO FIND :

The final speed of the baseball

FORMULAE USED :

change in momentum = mass × change in velocity

Δp = m × (Δv)

SOLUTION :

Let the final speed of the baseball be v.

We know that, Δp = m(Δv)

=> 11 = 0.15 × (v - u)

=> 11 = 0.15 × (v - 0)

=> v = 11/ 0.15

=> v = (11 × 100)/ 15

=> v = 220/ 3

=> v = 73.33 m/s