Question

A baseball player hits a ball out of the park and runs the bases which are 90 ft apart. What are the distance and displacement traveled?

Answer 1

Answer:

distance must be 90 ft and displacement will be 45

Answer 2

The distance traveled is 360 ft and the displacement is 0.

Given: A baseball player hits a ball out of the park and runs the bases which are 90 ft apart.

To Find: The distance and displacement traveled.

Solution:

• We know that displacement is the shortest distance between two points. It may or may not be in the direction of the distance.

• Displacement is a vector quantity and may be positive, negative, or zero.

• Distance is a scalar quantity and is always positive.

Coming to the numerical,

• The bases in a baseball game are designed in the form of a square, which has to be covered by the player for runs accordingly.

• When a baseball player hits a ball out of the park, it is called a home run if he runs through the square, covering all the bases, and reaches the home base without being adjudged out.

So, the distance covered by the baseball player is equal to the perimeter of the square.

The distance covered = ( 90 × 4 ) ft

                                     = 360 ft

Now, since the player starts and ends in the same position so the displacement becomes zero.

The displacement is = 0

Hence, the distance traveled is 360 ft and the displacement is 0.

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