A baseball player slides to a stop on level ground. Using energy considerations calculate the distance the 65.0-kg baseball player
slides, given that his initial speed is 6.00 m/s and the force of friction against him is a constant 450 N
15 m
200
2
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Answer:
2.57m
Explanation:
acceleration = 450 / 65 = 7 approx
using eqn of motion , a=7 , v=0 , u =6
s = 2.57
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