Question

A baseball with mass of 0.14 kg has an initial velocity of -38 m/s as it approaches a bat. The bat applies an average force that is much larger than the weight of the ball and the ball departs from the bat with a final velocity of +58 m/s. Determine the impulse applied to the ball by the bat. Assuming time of contact is 0.0016 s, find the average force exerted on the ball by the bat. Find the average force exerted on the bat by the ball

Answer 1

Answer:

the force exerted on the ball 1750N and bat -1750N

Explanation:

Answer 2

Answer:

Impulse applied is 13.44kg.m/s, average force exerted on the ball by the bat is 8400N and by the ball on the bat is - 8400N.

Explanation:

Given the mass of a baseball, m = 0.14 kg

Initial velocity, $v_i= -38 m/s$

Final velocity, $v_f= +58 m/s$

As the mass is not changed during the collision, using the impulse-momentum theorem, that is the change in the momentum of an object is equal to the impulse applied to it.

$\vec J=\Delta \vec P=m(v_f-v_i)$

Therefore, the impulse applied to the ball by the bat is

$\vec J=0.14\big((58-(-38)\big)=0.14\times 96=13.44kg.m/s$

Given the time of contact, t = 0.0016 s

Impulse is given by the product of force and the time of contact.

Therefore, the force is given by

$\vec F = \dfrac{\vec J}{t}$

Thus, the average force exerted on the ball by the bat is

$\vec F = \dfrac{13.44}{0.0016}=8400N$

According to Newton's third law, for every action, there is an equal and opposite reaction.

When an object A exerts a force on another object B, then the object B exerts a force equal in magnitude but opposite in direction on object A.

So, if the average force exerted on the ball by the bat is 8400N, then the same force of 8400N is applied on the bat by the ball but in opposite direction, which can be written as $-8400N$.

For more problems

https://brainly.in/question/5007633

https://brainly.in/question/9751610