Question

a basket contain four types of fruit weighting 20 kg in all. if 4 3/4 kg of these are apple 37/6 are oranges, 27/5 are pears and rest are papayas.what is the weight of papaya in the basket
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Answer 1

Answer:

The weight of Papayas is 3.684Kg.

Step-by-step explanation:

Given: A Basket Contains 4 types of fruits. With Total Weight 20Kg.

           Weight of Apples: 4 3/4Kg (Can also be written as 19/4Kg)

           Weight of Oranges: 37/6Kg

           Weight of Pears: 27/5Kg

           Weight of Papayas: To Find?

Now,

Let the weight of Papayas be x Kgs.

As we know,

Wgt.of Apples+ Wgt.of Oranges+ Wgt.of Pears+ Wgt.of Papayas = Wgt. of Basket                                                                    (Wgt. denoted for Weight)

19/4 + 37/6 + 27/5 + x = 20

57+74/12 + 27/5 + x = 20

131/12 + 27/5 + x = 20

655 + 324/60 + x = 20

979/60 + x = 20

16.316 + x = 20

x = 20 - 16.316

x = 3.684

Hence, the weight of Papayas is 3.684Kg.

Answer 2

${\huge{\boxed{\sf{\pink{Solution࿐}}}}}$

Total weight of fruit in basket = 20 kg

Total weight of an apple in basket = 19/4

Total weight of oranges = 37/4 kg

Total weight of pears = 27/5 kg

Total weight of papayas = ? let it be x

$\frac{19}{4} + \frac{37}{6} + \frac{27}{5} + x = 20 \\ lcm = 60 \\ \frac{19}{4} \times \frac{15}{15} + \frac{37}{6} \times \frac{10}{10} + \frac{27}{5} \times \frac{2}{2} \\ \frac{285}{60} + \frac{370}{60} + \frac{324}{60} + x = 20 \\ \frac{979}{60} + x = 20 \\ x = \frac{20}{1} - \frac{979}{ 60 } \\ lcm = 60 \\ x = \frac{20}{1} \times \frac{60}{60} - \frac{979}{60} \\ x = \frac{1200}{60} - \frac{979}{60} \\ x = \frac{1200 - 979}{60} = \frac{221}{60} \\ x = \frac{221}{60} \\ \\ therefore \: weight \: of \: the \: papayas \: is \: \frac{221}{60}$

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