A basket containing 8 blue balls, 4 black balls and 7 white balls. In how many ways 5 blue balls and 1 black ball and 4 white balls can be selected? A. 62 B. 4578 C. 7840 D. 35
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Answer:
Total white balls =2
Total black balls =3
Total red balls =4
The possibilities to draw three balls with atleast one black ball =(1 black+2 non black)+(2 black+1 non black)+(3 black+0 non black)
⇒3C1×6C2+3C2×6C1+3C3×6C0⇒3C1×6C2+3C2×6C1+3C3×6C0
⇒45+18+1⇒45+18+1
⇒64
Step-by-step explanation:
the Ans will be solve byy this process. Hope it's helpful to you
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