Question

A basket contains 15 apples and 10 oranges out of which 4 apples and 2 oranges are defective.What is the probability that either are apples or good

Answer 1

sample space

n(s) = 15+10+4+2=26

event A : good apples

n(A) = 19

P(A)=n(A)/n(S)

P(A)= 19/26

Answer 2

Answer:

0.76

Step-by-step explanation:

total no. of fruits= 15+10 = 25

defective fruits =4+2=6

good fruits = 25-6= 19

probability of good apples and orange = 19/25 = 0.76

hence the probability is 0.76

hope its helpfull