Math, asked by anmobossp1yye3, 9 months ago

A basket contains 3 red balls 5 blue and 2 green balls.If three balls are drawn at reandom what is the probasicity that none is blue?​

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Answered by ameliayahwak
1

Answer:

5/10

Step-by-step explanation:

The total number of balls in 10. There are 10 balls in the basket and 5 of those are blue. 10-5 = 5 meaning that 5/10 time you will not pull a blue ball. It is a 50% chance of pulling a blue ball

Answered by AbdallahAstrophysics
5

Answer:1/12

Step-by-step explanation:

At first draw, the total number of balls is 10. Among them, the number of balls that aren't blue is 5.

So probability of not being blue is = 5/10=1/2

At second draw, the total number of balls is 9. Among them the number of balls not blue is 4. So probability of not being blue is = 4/9

At third draw, total number of balls is 8. Among them, the number of balls not blue is 3. So probability of not being blue = 3/8

So, the probability of the ball for not being blue in three draws. = 1/2 * 4/9 * 3/8

= 1/12

Hope it helped.

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