A basket contains 3 red balls 5 blue and 2 green balls.If three balls are drawn at reandom what is the probasicity that none is blue?
Answers
Answer:
5/10
Step-by-step explanation:
The total number of balls in 10. There are 10 balls in the basket and 5 of those are blue. 10-5 = 5 meaning that 5/10 time you will not pull a blue ball. It is a 50% chance of pulling a blue ball
Answer:1/12
Step-by-step explanation:
At first draw, the total number of balls is 10. Among them, the number of balls that aren't blue is 5.
So probability of not being blue is = 5/10=1/2
At second draw, the total number of balls is 9. Among them the number of balls not blue is 4. So probability of not being blue is = 4/9
At third draw, total number of balls is 8. Among them, the number of balls not blue is 3. So probability of not being blue = 3/8
So, the probability of the ball for not being blue in three draws. = 1/2 * 4/9 * 3/8
= 1/12
Hope it helped.