A basket contains 4 red, 5 blue and 3 green marbles.
If three marbles are picked up at random what is
the probability that at least one is blue?
Answers
Answered by
4
Answer:
Total number of marbles = (4 + 5 + 3) = 12
Let E be the event of drawing 3 marbles such that none is blue.
Then, n (E) = number of ways of drawing 3 marbles out of 7 = 7C3
=7×6×53×2×1
= 35
And, n(S)=12C3
=12×11×103×2×1
= 220
∴P(E)=n(E)n(S)=35220=744
Required probability = 1- P (E) = (1−744)
=3744
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Answered by
0
Answer:
37/44
Step-by-step explanation:
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