A basket contains 40 eggs 8 out of them are rotten . If an egg is randomly picked then find the probability of it tobe rotten.Let the above egg is not rotten but not replaced. Another egg is randomly selected from the rest. Now find the probability of it tobe again rotten
amitnrw:
8/40 & 8/39
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Total no. of eggs=40
No.of rotten eggs=8
probability of egg to be rotten
=8/40
1/5
now,the eggs are not rotten
no.of rotten eggs=0
probability of eggs to be rotten =0
Answered by
1
Answer:
p(E) = total no. of favourable outcomes \ total no. of outcomes
P(E) = 8\40
P(E) = 5
p(E) = total no. of favourable outcomes \ total no. of outcomes
P(E) = 7\40 ( As one egg is removed before )
P(E) = 5.714285714285.....................................
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