a basket contains 6 apples 4 pear and 3 oranges if two are picked at random what is probability that both are pears
Answers
Answer:
There is a probability of 1/2 that the first is an apple. Given that, the probability is 5/11 that the second is an apple, and given those choices there is a probability of 4/10 that the third is an apple. Multiply these.
For at least one doughnut, it’s easier to calculate the probability that you only get apples and pairs. That’s exactly the same method as above. Subtract the result from 1.
For the third question, you have two doughnuts. So you pick one more and the probability that it’s a pear given that you have two doughnuts is 2/8. Does it matter whether you picked the doughnuts first or last, or picked the pear in the middle? That’s a question for you.
There are only a few basic rules. For the probability that two events both happen is the probability of the first multiplied by the probability that the second happens given the first happened. That was the rule for the first part.
Look up the rule for when you can add probabilities and you will know almost all you need to learn.
Answer:
Total no of fruits=6+4+3=13
No of pears=4
Probability (Getting a pear)=4/13