Question

a basket contains 6 apples 4 pear and 3 oranges if two are picked at random what is probability that both are pears​

Answer 1

Answer:

First, you have a total of 12 items in the bag (6A, 4P, 2D). You can imagine this number as the “total number of options available to you”. When you reach in (blindfolded) and take out first item, the probability that you pick an apple is 6/12 because there are 3 Apples in the bag. For the second pick, the odds change a little bit because there are only 5 Apples left among 11 items in total. So, the probability of picking an Apple in the second pick becomes 5/11. Similarly, for the third pick, there are only 4 Apples left among 10 items total. So, the odds of the third pick being an Apple is 4/10.

At this point, you have three probabilities, one each corresponding to the first, second and third picks being apple. Since we want all 3 to be apples, the overall probability will be a product of the three, i.e. (6/12) * (5/11) * (4/10) = 0.0909

If the question was asking to determine the probability of at least one of the picks being an apple, then the answer would have been (6/12) + (5/11) + (4/10)

If the question was asking to determine the probability of at least two of the picks being an apple, then the answer would have been:

Probability (two picks apple) + Probability (three picks apple) = (6/12) * (5/11) + (6/12) * (5/11) * (4/10)

Step-by-step explanation:

i hope it's helpful to you

Answer 2

The probability of getting both the pears are picked

GIVEN: A basket contains 6 apples 4 pears and 3 oranges if two are picked at random.
TO FIND The probability that both the pears are picked.​
SOLUTION:

As we are given in the question,

Number of apples in the basket = 6

Number of pears in the basket = 4

Number of oranges in the basket = 3

Therefore,

Total number of fruits in the basket = 6 + 4 + 3

Total number of fruits in the basket = 13

As we know,

Probability of getting a pear once = 4/13.

Similarly,

The probability of getting pear in the second pick = is 3/12

Probability of getting pear in both the picks = 4/13*3/12

Therefore,

The probability of getting pear in both the picks = 12/156.

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