Question

A basket contains 8 red, 4 black, 3 green flowers. If three flowers are picked at random, what is the probability that at least one is green

Answer 1

Step-by-step explanation:

P(e)=3/15

P(e)=1/5

this is the answer

Answer 2

Answer:

237/455

Step-by-step explanation:

Red Flowers = 8

Black Flowers = 4

Green Flowers = 3

Total numbers = 8 + 4 + 3

Total numbers = 15

P(one of the three is green)

= P(green) x P(not green) x P(not green)

= 3/15 x 12/14 x 11/13

= 66/455

P(two of the three are green)

= P(green) x P( green) x P(not green)

= 3/15 x 2/14 x 12/13

= 12/455

P(three of the three are green)

=P(green) x P(green) x P(green)

= 3/15 x 2/14 x 1/13

= 1/455

P(at least one of the three is green)

= 3(66/455 + 12/455 + 1/455)

= 3(79/455)

= 237/455