Question

a basket contains a certain number of blue, green, white ,black and red balls.each of these balls is assigned(as per colour) a point value of 1,1/2,1/5,1/x and 1/11 respectively where 5

Answer 1

Answer:

Let Q be the event that the drawn balls are white

A be the event that the bag contains 1 white ball

B be the event that the bag contains 2 white balls

C be the event that the bag contains 3 white balls

D be the event that the bag contains 4 white balls

E be the event that the bag contains 5 white balls

P(A)=1/5, P(B)=1/5, P(C)=1/5, P(D)=1/5, P(E)=1/5

P(Q/A)=

5

C

1

1

C

1

=

5

1

P(Q/B)=

5

C

1

2

C

1

=

5

2

P(Q/C)=

5

C

1

3

C

1

=

5

3

P(Q/D)=

5

C

1

4

C

1

=

5

4

P(Q/E)=

5

C

1

5

C

1

=1

using Baye's thorem,

P(A/Q)=

P(A) P(Q/A)+P(B) P(Q/B)+P(C) P(Q/C)+P(D) P(Q/D)+P(E) P(Q/E)

P(E) P(Q/E)

=

1/5.1/5+1/5.2/5+1/5.3/5+1/5.4/5+1/5.1.

1/5.1

=

1/5(1/5)+2/5+3/5+4/5+1

1/5

=

5

1+2+3+4+5

1

=

1+2+3+4+5

5

=

15

5

=

3

1