A basket contains four types of fruits weighing 20 kg in all. If 19/3 kg of these are apples,37/6 kg are oranges, 27/5 kg are pears and the rest are papayas. What is the weight of the papayas in the basket?
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Answered by
10
Answer:
19/3 + 37/6 + 27/5 + weight of pears = 20 kg
after taking LCM
(190+185+162)/30 + weight of pears =20
537/30 + weight of pears=20
weight of pears= 20 - 537 /30
weight of pears = 21/10
Answered by
2
Answer:
given that total weight of the basket =20 kg
which is the total weight of the apples,orange,pears and pappaya
to get the weight of the pappaya
weight of pappaya =total weight of the basket -weight of other fruits
= 20-(19/4+37/6+27/5)
=20-(19×6+37×4/6×4 +27/5)
= 20-(262/24+27/5)
=20-(262×5+24×7/5×24)
=20-(1478/120)
= 20-(12.33)
=7.67 kg
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