Question

A basket contains three types of fruits weighing 59/5 kg in all. If 80/9 kg of these are apples, 17/6 kg are oranges and the rest are mangoes. What is the weight of the mangoes in the basket?

Answer 1

Answer:

weight of apples + weight of Oranges + weight of Pears = Total weight of all types of fruits

\begin{gathered} \frac{73}{9} + \frac{19}{6} + weight of Pears = \frac{58}{3} kg \\ \\ Weight\ of\ Pears\ =\ \frac{58}{3} - \frac{73}{9} - \frac{19}{6} kg\\ \\ = \frac{6*58 - 2*73 - 3*19}{18} kg\\ \\ = \frac{ 348 - 146 - 57 }{18} kg\\ \frac{145}{18} kg \\ \\ = 8.05 kg \end{gathered}

9

73

+

6

19

+weightofPears=

3

58

kg

Weight of Pears =

3

58

−

9

73

−

6

19

kg

=

18

6∗58−2∗73−3∗19

kg

=

18

348−146−57

kg

18

145

kg

=8.05kg

Step-by-step explanation:

please

Answer 2

Answer:

$\frac{7}{90}$

Step-by-step explanation:

Weight of apples + weight of oranges + weight of mangoes = total weight of the fruits

Let x be the weight of mangoes

$\frac{59}{5} = \frac{80}{9} + \frac{17}{6} + x \\ \frac{59}{5} = \frac{480 + 153}{54} + x \\ \frac{59}{5} = \frac{633}{54} + x \\ \frac{59}{5} - \frac{633}{54} = x \\ \frac{3186 - 3165}{270} = x \\ \frac{21}{270} = x \\ \frac{7}{90} = x$

cross multiplication and cancellation are involved in this steps...HINT: Cancellation is done by 18th table

Hope this helps you!!