Question

a basket of orange is divided into three lots in the proportion 9:10:11. The smallest lot of oranges weighs 7 kg. what is the weight of each of the other two

Answer 1

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• Basket is divided in proportion = 9:10:11.

• Weight of smallest lot = 7Kg.

• So, let the weight of each lot be 9x, 10x and 11x respectively.

☆ ATQ,

$\sf\implies9x = 7 \: k g\\ \\ \sf\implies \: x = \frac{7}{9} kg \\ \\ \sf\implies \: x = 0.77 \: kg \\ \\ \sf( approx)$

☆ So,

▪︎ Weight of medium lot,

= 10x

= 10 × 0.77kg

= 7.7 kg.

▪︎ Weight of largest lot,

= 11x

= 11 × 0.77kg

= 8.47 kg.