Question

A basketball court 28 m by 15 m is surrounded by a path of uniform width 2.5 m. Find the area of the path. 660 m 2 420 m 2 240 m 2 225 m 2

Answer 1

Answer:

length of the big square = 100 m

length of the small square = 5 m

Side of the smaller square = Side of the bigger square - 2(width of the path)

= 100 - 2(5)

= 90 m

Area of the path = (100)² - (90)² = 10000 - 8100 = 1900 sq m

Cost of cementing at the rate of Rs 250 per 10 m² = 250 x 190 = Rs 47500