Question

A basketball is rolling rightward onto the court with a speed of 4.0 m/s and slows down with a constant leftward acceleration of magnitude 0.50 m/s^2 over 14m What is the velocity of the basketball after rolling for 14

Answer 1

Answer:

Given:-

Initial velocity (u) = 4m/s

Accleration = 0.50m/s^2

Distance = 14m

To find:-

Final velocity (v)

By applying, v^2 = u^2+2as

= 16+2×0.50×14

= 16+14

v^2 = √30

v = 5.47722m/s.

The velocity of the basket ball after rolling 14m is 5.47722m/s.