Question

A basketball team consists of 6 black and 6 white players. The players are to be paired in groups of two for the purpose of determining roommates. Of the pairings are done at random, what is the probability that none of the black players will have a white roommate

Answer 1

LET'S 6 WHITE PLAYERS BE

W1 W2 W3 W4 W5 W6

AND 6 BLACK PLAYERS BE

B1 B2 B3 B4 B5 B6

:.n(S)=36

THEREFORE ACCORDING TO THE EVENT:

n(A)=15

:.P(A)=n(A)/n(S)=15/36=2.4

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