a bat can hear sound of frequency upto 120khz Determine the minimum wavelength of same in air to be 344m/s
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Answer:
2.87x10^-3 m
Explanation:
Given that,
Frequency,f = 120 kHz
= 120x1000 Hz
= 120000 Hz
Velocity,v = 344 m/s
We know,
v= f x lamda
lamda = v/f
= 344/120000
= 2.87 x 10^-3 m
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