Question

A bat emits an ultrasonic sound of frequency 0.25 mhz. Calculate the time in which one vibration is completed.

Answer 1

Given frequency = 0.25 MHz
= 0.25×1000000
=250000 hz
We know that,
Frequency = 1/Time
250000 = 1/Time
Time= 1/250000 seconds.

Hope it'll help..........

Answer 2

Answer:

The time period in which one vibration is completed is 4000 seconds.

Explanation:

It is given that,

Frequency of the ultrasonic sound emitted by a bat, $f=0.25\ mHz=0.25\times 10^{-3}\ Hz$

If T is the time period in which one vibration is completed. It is given by :

$T=\dfrac{1}{f}$

$T=\dfrac{1}{0.25\times 10^{-3}}$

T = 4000 s

So, the time period in which one vibration is completed is 4000 seconds. Hence, this is the required solution.

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