Physics, asked by narmatha3782, 1 year ago

A bat releases a sound wave forward. It detects an echo 0.8s later. If the speed of sound in air os 300ms-1,how far is the bat away from the obstacle in front

Answers

Answered by sharmapuneet
6

Answer:

240 m

Explanation:

as distance =time taken ×speed.

=0.8×300=240m

Answered by Afreenakbar
0

Answer:

The bat is 240 meters away from the obstacle in front.

Explanation:

The sound wave takes twice as long to travel from the bat to the obstruction and back as it does to produce an echo.

Hence, the total amount of time is:

2  \times  0.8s = 1.6s

Since sound travels through air at a speed of300m {s}^{ - 1}, it can cover a distance of 300 metres in one second. In light of this, the sound wave's distance is:

Distance is determined by multiplying time and speed.distance equals 300ms⁻¹ times 1.6s

distance = speed  \times time \:  distance

 = 300m {s}^{ - 1}   \times  1.6s \:  distance \:

= 480  \: metres

The distance to the obstacle is half of this figure because the sound wave travelled to it and back.

distance \:  to  \: obstacle = \frac{  480 meters }{2}

 distance \:  to  \: obstacle = 240 \:  meters

Therefore, the bat is 240 meters away from the obstacle in front.

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