A bat releases a sound wave forward. It detects an echo 0.8s later. If the speed of sound in air os 300ms-1,how far is the bat away from the obstacle in front
Answers
Answer:
240 m
Explanation:
as distance =time taken ×speed.
=0.8×300=240m
Answer:
The bat is 240 meters away from the obstacle in front.
Explanation:
The sound wave takes twice as long to travel from the bat to the obstruction and back as it does to produce an echo.
Hence, the total amount of time is:
Since sound travels through air at a speed of, it can cover a distance of 300 metres in one second. In light of this, the sound wave's distance is:
Distance is determined by multiplying time and speed.distance equals 300ms⁻¹ times 1.6s
The distance to the obstacle is half of this figure because the sound wave travelled to it and back.
Therefore, the bat is 240 meters away from the obstacle in front.
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