Question

A batch of tiles, shown below, is placed into a bag. Ariana randomly draws one tile from the bag, records it, puts it back in the bag, and draws another tile. What is the probability that Ariana will draw a purple tile first and a red tile second? 10 green tiles, 5 purple tiles, 18 yellow tiles, 12 red tiles, 6 blue tiles, 4 brown tiles, and 5 white tiles. a. 17/60 b. 1/30 c. 1/5 d. 1/60

Answer 1

Answer:

1/60

Step-by-step explanation:

P(purple) = 5/60

P(red)= 12/60

P(purple then red) = (5/60)*(12/60)= 1/60

Answer 2

The probability would be $\frac{1}{60}$.

Step-by-step explanation:

Green tiles = 10

Purple tiles = 5

Yellow tiles = 18

Red tiles = 12

Blue tiles = 6

Brown tiles = 4

White tiles = 5

Total number of tiles in the bag = 10 + 5 + 18 + 12 + 6 + 4 +5

                                                     = 60 tiles

$P_{1}=\frac{\text{favorable events}}{\text{total outcome}}$

Probability to draw a purple tile first $P_{1}$ = $\frac{5}{60}$ = $\frac{1}{12}$

Probability to draw second tile red with replacement  $P_{2}=\frac{12}{60}=\frac{1}{5}$

Probability = $P_{1}\times P_{2}$

$=\frac{1}{12}\times \frac{1}{5}$

= $\frac{1}{60}$

Option d. $\frac{1}{60}$ will be the answer.

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