Question

A bats man hits a ball straight in the direction of of the blower without changing its initial speed of 12 m/s. if the mass of the ball is 0.15kg , determine the impulse imported to the ball. (Assume linear motion of the ball​

Answer 1

Answer:

Here, u=12ms−1,υ=−12ms−1 ,

m=0.5kg , Impulse = ?

As Impulse = Change in linear momentum ∴ Impulse =m(υ−u)=0.15(−12−12)

=−3.6Ns

Negative sigh shown that impulse is along negative x - axis , i.e., from the batsman to the bowler.

Explanation:

Answer 2

Answer:

Correct option is

A

3.6kgm/s

The initial momentum of ball P  

1

​

=m  

v

, after batsman hits ball and reverses its direction, momentum of ball P  

2

​

=−m  

v

 

Magnitude of change in momentum Δp=∣P  

2

​

−P  

1

​

∣=∣−2m  

v

∣=2m∣  

v

∣  

from data given in question m=0.15kg;∣  

v

∣=12m/s

ΔP=2×0.15×12=3.6kgm/s

Solve any question of Laws of Motion with:-

Explanation: