Question

A batsman deflects a ball by an angle 90° without changing its initial speed , which is equal to 54km/hr what is the impulse imparted into the ball (Mass of tge ball is 0.15 kg). ans is 3.18Ns​

Answer 1

Answer:

3.18Ns

Explanation:

u = 54 ×5/18 = 15m/s

u & v are at 90° hence Resultant velocity ∆v = √(u^2+v^2)

but u = v = 15m/s

∆v = √(225+225) = 21.21m/s

now, impulse = ∆P = m∆v

∆P = 21.21 × 0.15 = 3.18Ns

Answer 2

Answer:

Refer to the given attachment for the solution.