Question

A batsman deflects a ball by an angle of 120° without changing its initial speed of
20 m/s-1. What is the impulse imparted to the ball if its mass is 0.15 kg?
(a) 9 Js
(b) 6 Js
(c) 3 Js
(d) 1 Js​

Answer 1

Answer:

6Js

Explanation:

I=m(v-u)

=m(40)

=0.15(40)

=6Js

Answer 2

Answer:

The impulse of an object can be defined as the change in the momentum of the object.

the impulse imparted to the ball is 3 kg.m/s

the initial speed of the ball from point A, u = 20 m/s

the angle of deflection of the ball along BOP, θ = 120⁰/2 = 60⁰

mass of the ball, m = 0.15 kg

the final speed of the ball along B,  = u (in the reverse direction)

The initial momentum of the ball, P₁ = mucosθ

The final momentum of the ball is P₂ in the reverse direction to P₁.

the impulse imparted to the ball = change in momentum of the ball

J = ΔP = P₂ - P₁

J = m u cosθ - (-m u cosθ)

J = m u cosθ + m u cosθ

J = 2 m u cosθ

J = 2(0.15)20cos(60⁰)

J = 3 kg.m/s

Thus, the impulse imparted to the ball is 3 kg.m/s

To know more about impulse, refer: https://brainly.in/question/3203016

To know more about momentum, refer: https://brainly.in/question/54091389

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