Question

a batsman deflects a ball by an angle of 90 degree without changing its initial speed which is equal to 54 km per hour what is the impulse imparted to the ball mass of the ball is 0.15 kilogram​

Answer 1

Answer:

11.45 kg km per hour

Explanation:

inital momentum before the ball strikes

=mv i^(ball travels along positive x axis)

=0.15×54 i^

=8.1 i^ kg km per hour

final momentum= mv j^(ball travels along positive y axis)

=mv j^

=0.15×54 j^

=8.1 j^ kg km per hour

SO change in momentum

= 8.1 j^- 8.1 i^

=|8.1j^- 8.1i^|

=11.45 kg km per hour

But we know impulse = change in momentum

SO IMPULSE = 11.45 kg km per hour

Answer 2

Answer:

3.18ns

Explanation:

v=54km/hr  = 54x5/18 =15m/s

m=0.15

p=mv

15x0.15=2.25

$\sqrt{x} 2.25x^{2} +\sqrt{x} 2.25x^{2}$

3.18ns