Question

a batsman hit a ball of 200g with a force of 2N . find accleration of ball​

Answer 1

☯ Acceleration = 10m/s²

Given ,

• Mass = 200g
• Force = 2N

We need to find ,

• Acceleration = ?

Using , newtons second law ,

• F = m × a

Here , converting grams to kg because all units should be in S.I. units . So , 200g = 0.2 kg

⇒ 2 = 0.2 × a

⇒ 2 = 2/10 × a

⇒ 2 × 10 = 2 × a

⇒ 20 = 2a

⇒ a = 20/2

⇒ Acceleration = 10m/s²

Answer 2

Answer:-

Acceleration of the ball = 10 m/s²

Explanation:-

Mass of the ball = 200 g = 0.2 kg

Force = 2 N

According to newton 2nd law of motion

F = m×a

where

F = force

m = mass

a = acceleration

Substituting the values, we get:

2 = 0.2×a

2 = (2/10)×a

a = (20/2) m/s²

a = 10 m/s²

✔