a batsman hit the back the bowler strength in the direction of the balls without the change in the initial speed of the 12 metre per second if the mass of the ball is 0.15 kg determine the impulse in potent to the ball
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Mass=0.5kg
vels=12 m/sec
T time = 1sec
(F)force =12×0.5 =6N
there fore Impulse= F×T =6×1
= 6N/sec
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