A batsman hits back a ball straight in the direction of the bowler without changing its initial speed of 12 m/s. If the mass of the ball is 0.15 kg., determine the impulse imparted to ball (Assume linear motion of the ball).
Answers
Answered by
836
impulse = change in linear momentum .
initial momentum of ball= mu
=0.15 × 12 =1.8 kg.m/sec
final momentum of ball = -mu
= - 0.15 × 12 = -1.8 kgm/sec
now,
change in momentum of ball =final -initial
= -1.8 -1.8 = -3.6 kgm/sec
so,
change in momentum of bat = -change in momentum of ball
change in momentum of bat =3.6 kgm/s
now,
impulse imparted to ball =change in momentum of bat = 3.6 kgm/s
initial momentum of ball= mu
=0.15 × 12 =1.8 kg.m/sec
final momentum of ball = -mu
= - 0.15 × 12 = -1.8 kgm/sec
now,
change in momentum of ball =final -initial
= -1.8 -1.8 = -3.6 kgm/sec
so,
change in momentum of bat = -change in momentum of ball
change in momentum of bat =3.6 kgm/s
now,
impulse imparted to ball =change in momentum of bat = 3.6 kgm/s
pulipatisarath:
Thanks
Answered by
257
this is your correct answer
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