Question

A batsman hits back a ball straight in the direction of the bowler without changing it's initial speed of 12m/s. If the mass of the ball is 0.15kg, determine the impulse imparted to the ball

Answer 1

Answer:K=1/2mv²

=1/2*0.15*12²

=1/2*0.15*144

=72*0.15

...Calculate that

Answer 2

$\huge\underline{\underline{\bf \orange{Question-}}}$

A batsman hits back a ball straight in the direction of the bowler without changing it's initial speed of 12m/s. If the mass of the ball is 0.15kg, determine the impulse imparted to the ball

$\huge\underline{\underline{\bf \orange{Solution-}}}$

$\large\underline{\underline{\sf Given:}}$

Bowler threw the ball with initial velocity (u ) = 12m/s

Then , the batsman hit back the ball without change in its Velocity

⛬ v = - 12m/s

$\large\underline{\underline{\sf To\:Find:}}$

• Impulse.

We know that ,

✪${\boxed{\bf \blue{Impulse=Change\:in\:linear\: Momentum} }}$

$\implies{\sf mv-mu}$

$\implies{\sf m(v-u)}$

$\implies{\sf 0.15(-12-12)}$

$\implies{\sf 0.15×-24}$

$\implies{\bf \red{Impulse=-3.6m/s}}$

$\huge\underline{\underline{\bf \orange{Answer-}}}$

Impulse imparted to the ball is ${\bf \red{-3.6m/s}}$.