Question

A batsman hits back a ball straight in the direction of the bowler without
changing its initial speed of 12 m/s. If the mass of the ball is 0.15 kg,
determine the impulse imparted to the ball (Assume linear motion of the
ball)​

Answer 1

$\huge \sf \fcolorbox{red}{pink}{Solution :)}$

We know that ,

$\large \sf \fbox{Impulse = M(u - v)}$

Here ,

• Mass of ball (M) = 0.15 kg
• Initial Velocity (u) = 12 m/s
• Final velocity (v) = -12 m/s

Substitute the known values , we get

Impulse = 0.15(12 - (-12))

Impulse = 0.15 × (24)

Impulse = 3.6 Newton•sec

Hence , 3.6 Newton•sec impulse imparted to the ball

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Answer 2

The impulse imparted to the ball is 3.6 N-s

Explanation:

Given, Mass of the ball = 0.15 kg

Initial velocity = 12 m/s

Final velocity = -12 m/s ( negative sign indicate the direction of velocity)

• Impulse is defined as rate of change of linear momentum of the body also can be defined as product of force exerted to the body and time taken for the bodies in contact

              Impulse = change in linear momentum

                              = final momentum - initial momentum

                       I  = P₂ - P₁

                       I = m v = m u

                       I = 0.15 (-12) - 0.15 (12)

                       I = - 3.6 N s

As the impulse is imparted to ball I= 3.6 N s

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