Question

A batsman hits back a ball straight in the direction of the bowler without changing its initial speed of 15m/s. If the mass of the ball is 0.12 kg, determine the impulse imparted to the ball

Answer 1

hey...

here's ur answer... :)

initial momentum of ball= mu

=0.15 × 12 =1.8 kg m/s

final momentum of ball = -mu

= - 0.15 × 12 = -1.8 kg m/s

now,

change in momentum of ball = final - initial

= -1.8 -1.8 = -3.6 kgm/sec

so,

change in momentum of bat = -change in momentum of ball

change in momentum of bat =3.6 kgm/s

now,

impulse imparted to ball =change in momentum of bat = 3.6 kgm/s

hope it helps.... :)

Answer 2

${\huge{\underline{\underline{\mathfrak{\green{♡ANSWER♡}}}}}}$.

✪. Change in momentum=${0.15×12-(-0.15×12)}$

✪. ${3.6Ns,}$

✪. $\pink{\bold{\underline{\underline{Impulse}}}}$ = ${3.6Ns,}$

• In the direction from the batsman to the bowler .
• This is an example where the force on the ball by the batsman and the time of contact of the ball and the bat are difficult to know , but the impulse is readily calculated