Question

A batsman hits back a ball straight in the direction of the bowler without changing its initial speed of 12m/s. If the mass of the ball is 0.15kg. Determine the impulse impacted to the ball

Answer 1

impulse=change in momentum

initial momentum=mu=0.15*12=1.8 kgm/s

final momentum=mv= -0.15*12= -1.8 kgm/s

impulse impacted to bat=mv-mu= -1.8-1.8= -3.6 kgm/s

impulse impacted to ball= -impulse impacted on bat= -(-3.6)= 3.6 kgm/s

Answer 2

${\huge{\underline{\underline{\mathfrak{\purple{♡ANSWER♡}}}}}}$.

✪. Change in momentum=${0.15×12-(-0.15×12)}$

✪. ${3.6Ns,}$

✪. $\red{\bold{\underline{\underline{Impulse}}}}$ = ${3.6Ns,}$

• In the direction from the batsman to the bowler .
• This is an example where the force on the ball by the batsman and the time of contact of the ball and the bat are difficult to know , but the impulse is readily calculated.