Question

a batsman hits back a ball straight in the direction of the bowler without changing its initial speed of 12 m/s. If the mass of the ball is 0.15 kg, determine the impulse imparted to the ball. (Assume linear motion of the ball)

Answer 1

Answer:

Explanation:

Impulse = change in linear momentum .

initial momentum of ball= mu

=0.15 × 12 =1.8 kg.m/sec  

final momentum of ball = -mu  

= - 0.15 × 12 = -1.8 kgm/sec  

now,  

change in momentum of ball =final -initial  

= -1.8 -1.8 = -3.6 kgm/sec  

so,  

change in momentum of bat = -change in mnow,

impulse imparted to ball =change in momentum of bat = 3.6 kgm/s

omentum of ball  

change in momentum of bat =3.6 kgm/s