a batsman hits the back of ball with mass of ball 0.15 kg .if ball moves linearly without changing the direction with intial sped 12m/second. calculate the impulse.
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1
Answer:
Explanation:
Change in momentum +0.15×12−(−0.15×12)=3.6 N s
Impulse = 3.6 N s in the direction from the batsman to the bowler.
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Explanation:
mass of ball= 0.15kg
velocity =12m/s
acceleration =0, because the ball is moving linearly so there is no change in velocity
Impulse = pf-pi
(0.15×12)-(0.15×12)
0kgm/s² OR 0N
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