Question

a batsman hits the back of ball with mass of ball 0.15 kg .if ball moves linearly without changing the direction with intial sped 12m/second. calculate the impulse.​

Answer 1

Answer:

Explanation:

Change in momentum +0.15×12−(−0.15×12)=3.6 N s

Impulse = 3.6 N s in the direction from the batsman to the bowler.

Hope it helped you...

Answer 2

Explanation:

mass of ball= 0.15kg

velocity =12m/s

acceleration =0, because the ball is moving linearly so there is no change in velocity

Impulse = pf-pi

(0.15×12)-(0.15×12)

0kgm/s² OR 0N