a batsman in his 11th innings makes a score of 68 runs and there by increases his average score by 2 what is his average score after the 11th innings
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2
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kiranmishra:
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let the score made in 10 inninsgs be x runs then avg score =x/10 now he score 68 in 11 th inning therefor e avg after 11th inning=(x+68)11 now according to question previous avg is increased by 2 therefore( x+68)÷11=2+x/10. (x+68)/11=(20+x)/10. from here we get x=460. so avg scre after 11 innings =(460+68)/11=48
now it is more confusing
Answered by
13
let the av.score in first 10 match be x
so total runs =10x
now av. score is x+2
so ,10x =(x+2)11-68
10x =11x+22-68
10x =11x-44
x=44.
so av score after 11th inn. =46
so total runs =10x
now av. score is x+2
so ,10x =(x+2)11-68
10x =11x+22-68
10x =11x-44
x=44.
so av score after 11th inn. =46
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