Question

A batsman in his 12th innings, makes a score of 63 runs and thereby increased his average score by 2 runs. The average of his score after 12th innings is

Answer 1

Solution :

Let the total number of runs in 11 innings be "x".

So, the average number of runs in 11 innings is x/11.

Let the total number of runs in 12 innings after scoring 63 runs in 12th innings be x + 63.

Average number of runs in 12th innings is = (x + 63)/12

(x + 63)/12 = (x/11) + 2

=> (x + 63)/12 = (x + 22)/11

=> 11(x + 63) = 12(x + 22)

=> 11x + 693 = 12x + 264

=> 693 - 264 = 12x - 11x

=> 429 = x

.°. x = 429

The average of his score after 12th innings

= (x + 63)/12

Putting the value of "x" in this equation.

= (x + 63)/12

= (429 + 63)/12

= 492/12

= 41

Therefore, the average of his score after 12th innings is 41 runs.

Answer : 41

Answer 2

Answer:

The average of his score after 12th innings is 41

Step-by-step explanation:

Let, the total runs in first 11 innings is x

Average runs in first 11 innings is x/11

The total runs in 12 innings after scoring 63 runs in 12th innings be x + 63

Then, the average runs in 12 innings is (x + 63)/12

By the given condition,

(x + 63)/12 = x/11 + 2

⇒ (x + 63)/12 = (x + 22)/11

⇒ 11 (x + 63) = 12 (x + 22)

⇒ 11x + 693 = 12x + 264

⇒ 12x - 11x = 693 - 264

⇒ x = 429

Therefore, the average of his score after 12th innings be (429 + 63)/12

= 492/12 = 41